Factor the expression by grouping. First, the expression needs to be rewritten as 7x^{2}+ax+bx-20. To find a and b, set up a system to be solved.

You are watching: Factor 7x^2-31x-20

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -140.

displaystyle{left({9}{x}-{5}

ight)}{left({x}+{4}

ight)} Explanation:Given – displaystyle{9}{x}^{{2}}_{31}{x}-{20} Find the product of -20 and 9.It is -180Find two numbers, the …

7×2-31x-20 Final result : (x – 5) • (7x + 4) Step by step solution : Step 1 :Equation at the end of step 1 : (7×2 – 31x) – 20 Step 2 :Trying to factor by splitting the middle term …

7×2+3x-2=0 Two solutions were found : x =(-3-√65)/14=-0.790 x =(-3+√65)/14= 0.362 Step by step solution : Step 1 :Equation at the end of step 1 : (7×2 + 3x) – 2 = 0 Step 2 :Trying to …

5×2+31x-28 Final result : (5x – 4) • (x + 7) Step by step solution : Step 1 :Equation at the end of step 1 : (5×2 + 31x) – 28 Step 2 :Trying to factor by splitting the middle term …

x2+31x-32=0 Two solutions were found : x = 1 x = -32 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+31x-32 The first term is, x2 its …

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7×2-31x-20=0 Two solutions were found : x = -4/7 = -0.571 x = 5 Step by step solution : Step 1 :Equation at the end of step 1 : (7×2 – 31x) – 20 = 0 Step 2 :Trying to factor by splitting …

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Factor the expression by grouping. First, the expression needs to be rewritten as 7x^{2}+ax+bx-20. To find a and b, set up a system to be solved.

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -140.

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=aleft(x-x_{1}

ight)left(x-x_{2}

ight), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: frac{-b±sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

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Factor the original expression using ax^{2}+bx+c=aleft(x-x_{1}

ight)left(x-x_{2}

ight). Substitute frac{4}{7} for x_{1} and -5 for x_{2}.